The wavelength of light from the spectral emission line of sodium is 590 nm. Find the kinetic energy at which the electron would have the same de-Broglie wavelength.

 

Answers (1)
S safeer

\lambda=\frac{h}{\sqrt{2mK}}

K=\frac{h^2}{2m\lambda^2}

K=\frac{(6.63\times 10^{-34})^2}{2\times 9.1\times 10^{-31}\times (590)^{2}\times 10^{-18}}

K=6.94\times 10^{-25}J

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