There are 5 consecutive integers in ascending order. the avg of the first and twice the last is equal to the avg of the other 3.find the 1st integer.

Answers (1)

Assume the 5 integers be x , x+1 , x+ 2 , x+3 , x+4.

ATQ

{ x+ 2(x+4)}/2 = {x+1+x+2+x+3}/3

3( 3x+8) = 2(3x+6)

9x-6x = 12 -24

3x = -12 => x = -4

Hence the first integer is -4.

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