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There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:

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\\ Let \ the \ number \ of \ students \ in \ rooms \ $A$ \ and \ $B$ \ be\ $x$\ and \ $y$ \ respectively.\\ \\ Then, $x-10=y+10 \Rightarrow x-y=20 \ldots$ and $x+20=2(y-20) \Rightarrow x-2 y=-60 \ldots$ \\ \\ Solving (i) and (ii) \ we \ get:\ $x=100, y=80$ \\ \\ $\therefore$ \ The \ required \ answer \ $A=100$

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Deependra Verma

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