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Three bell ring at an arrival of 20, 25 and 30 minutes respectively it they ring together at 11:00 a.m. to at what time they will ring together again

Answers (1)

In order to  find the minimum time,we have to find the LCM of 20,25,30
20=2*2*5
25=5*5
30=3*2*5
LCM =2*2*3*5*5
        =300 minutes
        =5 hours
therefore,at 4 p.m, they will meet again

Posted by

Satyajeet Kumar

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