Three bell ring at an arrival of 20, 25 and 30 minutes respectively it they ring together at 11:00 a.m. to at what time they will ring together again
Answers (1)
In order to find the minimum time,we have to find the LCM of 20,25,30
20=2*2*5
25=5*5
30=3*2*5
LCM =2*2*3*5*5
=300 minutes
=5 hours
therefore,at 4 p.m, they will meet again