Three identical dice are rolled once . the probability that the same number will appear on each of them is

Answers (1)

Solution:   a a a  occurs in  ^6c_1=6 ways

                  a a b occurs in   2! ^6c_2=30 ways

                  a b c occurs in ^6c_3=20 ways

            	herefore      The number of different outcomes is  6+30+20=56

                      out of which 6  are favourable case

            The desired probability frac656=frac328.

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