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Three identical dice are rolled once . the probability that the same number will appear on each of them is

Answers (1)

D Deependra Verma

Solution: a a a occurs in $^6c_1=6$ ways

a a b occurs in $2! ^6c_2=30$ ways

a b c occurs in $^6c_3=20$ ways

$herefore$ The number of different outcomes is $6+30+20=56$

out of which $6$ are favourable case

The desired probability $frac656=frac328.$

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