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Two adjacent sides of cyclic quadrilateral are 2 and 5 and the angle between them is 60 degree . its third side is 3 , the fourth side is

Answers (1)

D Deependra Verma

Solution: If $x$ is the fourth side , then

$Rightarrow$ $2^2+5^2-2cdot 2cdot 5cos 60^circ=x^2+3^2+2xcdot 3cos60^circ$

$Rightarrow$ $x^2+3x-10=0Rightarrow x=2.$

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