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  • Two cells each of EMF 1.5 volt are joined in series and send 1.0 ampere current in an external resistor if the same cells are joined in parallel then they send 0.6 ampere current in the same resistor what is the internal resistance of each cell​

Two cells each of EMF 1.5 volt are joined in series and send 1.0 ampere current in an external resistor if the same cells are joined in parallel then they send 0.6 ampere current in the same resistor what is the internal resistance of each cell​

Answers (1)

Let internal resistance be r and external resistance be R

In series combination, 

Net emf, E=1.5+1.5=3V

Net Resistance=R+2r

In parallel combination,

Net emf, E=1.5 V

Net resistance=(R+r/2)

From equation 1 and 2, we get:-

r=1/3

Posted by

shubham.krishnan

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