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  • Two identical coils P and Q each of radius R are lying in perpendicular planes such that they have a common centre. Find the magnitude and direction of the magnetic field at the common centre when they carry currents equal to I and <img alt="\sqrt

Two identical coils P and Q each of radius R are lying in perpendicular planes such that they have a common centre. Find the magnitude and direction of the magnetic field at the common centre when they carry currents equal to I and \sqrt{3}I respectively.

 

 
 
 
 
 

Answers (1)

The magnitude field  for P

B_{1}=\frac{\mu _{0}I}{2R}

and for Q

B_{2}=\frac{\mu _{0}\sqrt{3}I}{2R}

Now, the magnitude of the Resultant magnetic field;-

B=\sqrt{B^{2}_{1}+B^{2}_{2}}

B=\sqrt{\left ( \frac{\mu _{0}I}{2R} \right )^{2}+\left ( \frac{\mu _{0}\sqrt{3}I}{2R} \right )^{2}}

B=\frac{\mu _{0}I}{R}

Now, the direction of the resultant magnetic field.

\tan \theta =\frac{B_{1}}{B_{2}}

Therefore, \theta =30^{\circ}

Posted by

Safeer PP

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