Two long straight wires carrying currents of 2 A and 5 A in the same direction are kept parallel, 10 cm apart from each other. Calculate the force acting between them and write its nature.

 

 

Answers (1)
S safeer


Given,
          Current in wire A = IA = 2A
          Current in wire B = IB = 5A
Distance between wire A and B = d = 10cm
The magnetic force per and length of wire is,
 \frac{F}{p}= \frac{\mu _{0}I_{A}I_{B}}{2\pi d}
     = \frac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 10\times 10^{-2}}
F= 2\times 10^{-5}N
Since the current is in the same direction the force will be attractive

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