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Two resistors R_{1}and R_{2} of 4\; \Omega and 6\; \Omega are connected in parallel across a battery. The ratio of power dissipated in them,P_{1}:P_{2} will be  
Option: 1 4:9
Option: 2 3:2
Option: 3 9:4
Option: 4 2:3

Answers (1)

Power 

P=\frac{V^2}{R}

For parallel circuits, the voltage across the branches are the same. Therfore the ratio of power

\frac{P_1}{P_2}=\frac{R_2}{R_1}=\frac{6}{4}=\frac{3}{2}

 

Posted by

Safeer PP

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