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Using factor theorem show that (y+3) is a factor of f(y) = y4 + y3 – 7y2 – y+6.​
Answers (1)
If (y+3) is a factor of f(y) = y4 + y3 – 7y2 – y+6 then f(-3) = 0
f(-3) = (-3)4 + (-3)3 – 7(-3)2 –(-3)+6
f(-3) = 81 - 27 - 63 + 3 + 6
f(-3) = 0
Hence (y+3) is factor of f(y) = y4 + y3 – 7y2 – y+6 .
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