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What is the effect on the interference fringes in Young’s double slit experiment due to each of the following operations? Justify your
answers. 

(a) The screen is moved away from the plane of the slits.
(b) The separation between slits is increased.
(c) The source slit is moved closer to the plane of double slit.

 

 
 
 
 
 

Answers (1)

a) Fringe width \beta\ \propto D. Therefore the fringe width increases when D is increased.

b) \beta\ \propto 1/d, therefore when d is increased the fringe width decreases.

c) If s is the size of the source and S is distant of the source from the plane of the two slits, then for interference fringes to see, the condition is 

\frac{s}{S}<\frac{\lambda}{d}

The fringe disappears because

 \frac{s}{S}<\frac{\lambda}{d}\ not\ satisfied

 

Posted by

Safeer PP

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