What is the normality of solution obtained by mixing 100 ml of 0.2 M H2SO4 with 100 ml of 0.2 M NaOH?

Answers (1)
S Sumit

N = gram-equivalent/ volume(lt.)

When two or more compounds or elements react together their gram-equivalent will be equal in simple way, 10 gm-eq of an acid will react completely with 10 gm-eq of base,

In given problem,

gm-eq. of H2SO4 = N*V(lt.)

and N = n*M where, M = molarity and n = basicity or acidity of an acid or base.

gm-eq of H2SO4 = 100*2*0.2*0.001 =0.04gm-eq

gm-eq of NaOH = 100*0.2*1*0.001 =0.02

Remaining gm-eq of H2SO4 = 0.04–0.02

= 0.02gm-eq

Now,

gm-eq. = N*V = 0.02

Total volume =200ml = 0.2 lt.

N*0.2 = 0.02 = 0.1N

Hence Normality will be 0.1 N 

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