N = gram-equivalent/ volume(lt.)
When two or more compounds or elements react together their gram-equivalent will be equal in simple way, 10 gm-eq of an acid will react completely with 10 gm-eq of base,
In given problem,
gm-eq. of H2SO4 = N*V(lt.)
and N = n*M where, M = molarity and n = basicity or acidity of an acid or base.
gm-eq of H2SO4 = 100*2*0.2*0.001 =0.04gm-eq
gm-eq of NaOH = 100*0.2*1*0.001 =0.02
Remaining gm-eq of H2SO4 = 0.04–0.02
= 0.02gm-eq
Now,
gm-eq. = N*V = 0.02
Total volume =200ml = 0.2 lt.
N*0.2 = 0.02 = 0.1N
Hence Normality will be 0.1 N