What is the number of photons of light with a wavelength of 4000 pm that provide 1J of energy?

Answers (1)
S Sumit

Given, λ = 4000 pm = 4000×10-12 m = 4×10-9 m

E = Nhν = Nhc/λ
Therefore, N = E×λ/h×c = (1J×4×10-9 m)/(6.626×10-34 Js×3.0×10ms-1) = 2.012×1016 photons.

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