What is the oxidation number of chromium in K2Cr2O7 molecule.

Answers (1)
S Sumit

Let oxidation number of Cr be x

According to the balancing of the equations- 
2+2x-14=0
2x-12=0
2x=12
x=6

Therefore the Oxidation Number of Cr in K2Cr2O7 is 6.

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