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  • What is the remainder when x^4+4x^3-5x^2-6x+7 is divided by x-2

What is the remainder when x^4+4x^3-5x^2-6x+7 is divided by x-2

Answers (1)

f(x)= x4+4x3-5x2-6x+7

When f(x) is divided by x-2

Remainder is f(2) = 24+4x23-5x22-6x2+7=23

Posted by

Ravindra Pindel

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