When unpolarized light is incident on the interface separating the rarer medium and the denser medium, Brewster angle is found to be 60^{\circ}. Determine the refractive index of the denser medium.

 

 

 

 
 
 
 
 

Answers (1)

The Brewster angle (\theta _{p}) is given , 60^{\circ}.

The Brewster law states that the tangent of the polarizing angle of incident of a transparent medium is equal to the refractive index of the medium.

 \theta _{p}= Brewster's angle

 \tan \theta _{p}=\mu

 \because \tan 60^{\circ}={\mu}

 \mu =\sqrt{3},

Assuming the rarer medium as air.

Hence, the refractive index of the denser medium is \sqrt{3}.

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