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y = e^ax . cos (bx +c) find dy/dx .

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Solution :  We have , y= e^ax cos (bx +x)

Using product rule , we get 

               fracmathrmd ymathrmd x=e^ax imes fracmathrmd \cos (bx+c)\mathrmd x+cos(bx+c) imes fracmathrmd (e^ax)mathrmd x

Rightarrow           fracmathrmd ymathrmd x=e^ax imes -sin(bx+c) imes fracmathrmd (bx+c)mathrmd x+cos(bx+c) imes e^ax imes fracmathrmd (ax)mathrmd x

Rightarrow          fracmathrmd ymathrmd x=e^ax imes -sin(bx+c) imes b+ cos (bx+c) imes e^ax imes a

Rightarrow            fracmathrmd ymathrmd x=e^ax-bsin(bx+c) +a cos (bx+c)

                

 

Posted by

Deependra Verma

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