Q

He said to find out internal energy ^U ?

so i got ans is;

formula ; W=P*(V2-V1)

OPTIONS;A;-500j

B;  -505j

C; +505j

D;1136.25j

MY ANS ; -500J

A Abhishek Sahu

It is given that the process is adiabatic

Hence, $\Delta U +W =0$

$\Rightarrow \Delta U = -W$

$W = P\Delta V$

$W = 2.5\times 1.01\times 10^{5}\left ( 4.5 -2.5 \right )10^{-3}$

$W = 505\: J$

$\Delta U = -505 J$

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A Ankit Dutt

According to Bohr's model -

1. Force of attraction between the nucleus and an electron is equal to centripetal force.

2. $mvr=\frac{nh}{2\pi }$

n = principal quantum number.

3. Energy can be absorbed or emitted when electron transfers between the orbits  $E_{1}-E{_{2}}=h\nu$
The orbital angular momentum is given by $\sqrt{l(l+1)}\frac{h}{2\pi }$ where l is the azimuthal quantum number for p orbital, $l=1$

$\therefore$ orbital angular momentum = $\sqrt{(1)(1+1)} \frac{h}{2\pi }$

$= \sqrt{2} \frac{h}{2\pi } = \frac{h}{\sqrt{2}\pi }$

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A Ankit Dutt

Moles of urea = Number of molecules/Avogadro number
=> 6.02x10^20/6.02x10^23
=> 10^-3 moles

Now, concentration or molarity = Number of moles/ volume in litre
=> M = (10^-3/100)*1000
=> M = 10^-2 M

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