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  • Explain solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise multiple choice questions question 8 maths textbook solution

Explain solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise multiple choice questions question 8 maths textbook solution

Answers (1)

Answer:

              10

Hint:

              To solve this equation we use E\left(X^{2}\right)=\sum_{i=0}^{n} X_{i}^{2} P(X)

Given:

              

X 1 2 3 4
P\left ( X \right ) \frac{1}{10} \frac{1}{5} \frac{3}{10} \frac{2}{5}

Solution:

E\left(X^{2}\right)=\sum_{i=0}^{n} X_{i}^{2} P(X)

E\left(X^{2}\right)=\frac{1}{10}+\frac{4}{5}+\frac{27}{10}+\frac{32}{5}

 

X X^{2} P\left ( X \right ) X^{2}P\left ( X \right )
1 1 \frac{1}{10} \frac{1}{10}
2 4 \frac{1}{5} \frac{4}{5}
3 9 \frac{3}{10} \frac{27}{10}
4 16 \frac{2}{5} \frac{32}{5}

 

=\frac{1+8+27+64}{10}

=\frac{100}{10}=10

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