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Please solve RD Sharma class 12 chapter 26 Direction Cosines and Direction Ratios exercise Fill in the blanks question 1 maths textbook solution

Answers (1)

Final Answer : \sqrt{a^{2}+c^{2}}
 

Hint:

Use Distance Formula
 

Given:

Point P(a,b,c)
 

To Find: 

Distance of point P from y -axis
 

Solution:
The distance of the point (a,b,c) from y-axis will be the perpendicular distance from point (a,b,c) to y-axis whose co-ordinates are (0,b,0)
Distance formula is
\begin{aligned} &d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}+\left(z_{2}-z_{1}\right)^{2}} \\\\ &d=\sqrt{(0-a)^{2}+(b-b)^{2}+(0-c)^{2}} \end{aligned}

where \left(x_{1}, y_{1}, z_{1}\right)=(a, b, c) \text { and }\left(x_{2}, y_{2}, z_{2}\right)=(0, b, 0)

d=\sqrt{a^{2}+c^{2}}

Therefore distance from y axis is \sqrt{a^{2}+c^{2}}

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