Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31.1 question 1 sub question 3 maths textbook solution

Provide solution for RD Sharma maths class 12 chapter 31 Mean and Variance of a Random Variable exercise 31.1 question 1 sub question 3 maths textbook solution

Answers (1)

Answer: The given distribution of probability is a probability distribution

Hint: \sum P\left ( x=n \right )=1

Given:          

X 0 1 2 3 4
P\left ( X \right ) 0.1 0.5 0.2 0.1 0.1

Solution:

P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)

=0.1+0.5+0.2+0.1+0.1

=1

So, the given distribution of probability is a probability distribution.

Posted by

Infoexpert

View full answer

Similar Questions

Latest Question