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6.  A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?

Distance travelled by vehicle in 2.4 litres of petrol = 43.2 km

Distance travelled by vehicle in 1 litre of petrol:

=\frac{43.2}{2.4}=\frac{432}{24}\times\frac{10}{10}=18

Hence Distance travelled by vehicle in 1 litre is 18 km.

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Posted by

Pankaj Sanodiya

5.   Find:

             (i)\; 7\div 3.5         (ii)\; 36\div 0.2            (iii)\; 3.25\div 0.5          (iv)\; 30.94\div 0.7

             (v)\; 0.5\div 0.25      (vi)\; 7.75\div 0.25    (vii)\; 76.5\div 0.15     (viii)\; 37.8\div 1.4

              (ix)\; 2.73\div 1.3 

As we know, while dividing decimal, we first express the decimal in term of fraction and then divides it,

And

Dividing by a number is equivalent to multiplying by the reciprocal of that number. 

So

(i)\; 7\div 3.5 

\; 7\div 3.5=7\div \frac{35}{10}=7\times\frac{10}{35}=\frac{70}{35}=2

 (ii)\; 36\div 0.2           

\; 36\div 0.2=36\div\frac{2}{10}=36\times\frac{10}{2}=180

(iii)\; 3.25\div 0.5         

\; 3.25\div 0.5=\frac{325}{100}\div\frac{5}{10}=\frac{325}{100}\times\frac{10}{5}=\frac{65}{10}=6.5

(iv)\; 30.94\div 0.7

\; 30.94\div 0.7=\frac{3094}{100}\div\frac{7}{10}=\frac{3094}{100}\times\frac{10}{7}=\frac{442}{10}=44.2            

(v)\; 0.5\div 0.25     

\; 0.5\div 0.25=\frac{5}{10}\div\frac{25}{100}=\frac{5}{10}\times\frac{100}{25}=\frac{10}{5}=2

(vi)\; 7.75\div 0.25    

\; 7.75\div 0.25=\frac{775}{100}\div\frac{25}{100}=\frac{775}{100}\times\frac{100}{25}=31

(vii)\; 76.5\div 0.15  

 \; 76.5\div 0.15=\frac{765}{10}\div\frac{15}{100}=\frac{765}{10}\times\frac{100}{15}=510

 (viii)\; 37.8\div 1.4

 \; 37.8\div 1.4=\frac{378}{10}\div\frac{14}{10}=\frac{378}{10}\times\frac{10}{14}=27           

(ix)\; 2.73\div 1.3 

\; 2.73\div 1.3=\frac{273}{100}\div\frac{13}{10}=\frac{273}{100}\times\frac{10}{13}=\frac{21}{10}=2.1

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Posted by

Pankaj Sanodiya

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4.    Find:

             (i)\; 7.9\div 1000         (ii)\; 26.3\div 1000            (iii)\; 38.53\div 1000          (iv)\; 128.9\div 1000

             (v)\; 0.5\div 1000        

As we know, while dividing a decimal number by 1000 we shift the decimal to left by 3 digits, So

(i)\; 7.9\div 1000 

\; 7.9\div 1000=0.0079

 (ii)\; 26.3\div 1000

\; 26.3\div 1000=0.0263

(iii)\; 38.53\div 1000 

\; 38.53\div 1000=0.03853

(iv)\; 128.9\div 1000

\; 128.9\div 1000=0.1289

(v)\; 0.5\div 1000        

\; 0.5\div 1000=0.0005

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Pankaj Sanodiya

3.  Find:

  (i)\; 2.7\div 100         (ii)\; 0.3\div 100            (iii)\; 0.78\div 100          (iv)\; 432.6\div 100

    (v)\; 23.6\div 100       (vi)\; 98.53\div 100    

As we know while dividing a decimal number by 100, the decimal point gets shifted to left by two digits.

So

(i)\; 2.7\div 100

\; 2.7\div 100=0.027

(ii)\; 0.3\div 100 

\; 0.3\div 100=0.003

(iii)\; 0.78\div 100

 \; 0.78\div 100=0.0078

(iv)\; 432.6\div 100

\; 432.6\div 100=4.326

(v)\; 23.6\div 100  

\; 23.6\div 100=0.236

(vi)\; 98.53\div 100    

\; 98.53\div 100=0.9853

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Posted by

Pankaj Sanodiya

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2.  Find:

 (i)\; 4.8\div 10         (ii)\; 52.5\div 10            (iii)\; 0.7\div 10               (iv)\; 33.1\div 10

  (v)\; 272.23\div 10       (vi)\; 0.56\div 10     (vii)\; 3.97\div 10

As we know, When we divide a decimal number by 10, the decimal point gets shifted by one digit in the left.

So

(i)\; 4.8\div 10 

\; 4.8\div 10=0.48

(ii)\; 52.5\div 10

\; 52.5\div 10=5.25

(iii)\; 0.7\div 10  

\; 0.7\div 10=0.07        

(iv)\; 33.1\div 10

\; 33.1\div 10=3.31

(v)\; 272.23\div 10

\; 272.23\div 10=27.223

 (vi)\; 0.56\div 10

\; 0.56\div 10=0.056

 (vii)\; 3.97\div 10

\; 3.97\div 10=0.397

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Posted by

Pankaj Sanodiya

1.   Find:

             (i)\; 0.4\div 2           (ii)\; 0.35\div 5         (iii)\; 2.48\div 4            (iv)\; 65.4\div 6

             (v)\; 651.2\div 4     (vi)\; 14.49\div 7      (vii)\; 3.96\div 4           (viii)\; 0.80\div 5

            

As we know, while dividing decimal, we first express the decimal in term of fraction and then divides it,

And

Dividing by a number is equivalent to multiplying by the reciprocal of that number. So

So

  (i)\; 0.4\div 2     

\; 0.4\div 2=\frac{4}{10}\div2=\frac{4}{10}\times\frac{1}{2}=\frac{2}{10}=\frac{1}{5}

(ii)\; 0.35\div 5        

\; 0.35\div 5=\frac{35}{100}\div5=\frac{35}{100}\times\frac{1}{5}=\frac{7}{100}=0.07

(iii)\; 2.48\div 4    

\; 2.48\div 4=\frac{248}{100}\div4=\frac{248}{100}\times\frac{1}{4}=\frac{62}{100}=0.62

 (iv)\; 65.4\div 6

\; 65.4\div 6=\frac{654}{100}\div6=\frac{654}{100}\times\frac{1}{6}=\frac{109}{100}=1.09

 (v)\; 651.2\div 4

\; 651.2\div 4=\frac{6512}{10}\div4=\frac{6512}{10}\times\frac{1}{4}=\frac{1628}{10}=162.8

 (vi)\; 14.49\div 7    

\; 14.49\div 7=\frac{1449}{100}\div7=\frac{1449}{100}\times\frac{1}{7}=\frac{207}{100}=2.07

(vii)\; 3.96\div 4        

\; 3.96\div 4=\frac{396}{100}\div4=\frac{396}{100}\times\frac{1}{4}=\frac{99}{100}=0.99

 (viii)\; 0.80\div 5

 \; 0.80\div 5=\frac{80}{100}\div5=\frac{80}{100}\times\frac{1}{5}=\frac{16}{100}=0.16 

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Posted by

Pankaj Sanodiya

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