Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
Filter By
Clear Filter

All Questions

3.9 The resistance of a conductivity cell containing 0.001M KCl solution at 298  K is 1500 ohm . What is the cell constant if conductivity of 0.001M KCl solution  at 298 K is 0.146\times10^{-3}\ S cm^{-1}.

We are given with conductivity of cell   \kappa =  0.146\times10^{-3}\ S cm^{-1} and  resistance R =  1500 \Omega.

Also,                                  Cell constant =  \kappa\times R

or                                                              =  0.146\times 10^{-3}\times 1500

or                                                              = 0.219\ cm^{-1}

View Full Answer(1)
Posted by

Devendra Khairwa

filter_img