When cell has stalled DNA replication fork, which checkpoint should be predominantly activated?
G1/S
G2/M
M
Both G2 M and M
G2/M should be activated as the cell has stalled DNA replication fork.
View Full Answer(1)At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires 375 mL air containing 20% O2 by volume for complete combustion. After combustion, the gases occupy 330 mL. Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :
Option: 1 C4H8
Option: 2 C4H10
Option: 3 C3H6
Option: 4 C3H8
Volume of N2 in air = 375 × 0.8 = 300 ml
Volume of O2 in air = 375 × 0.2 = 75 ml
15ml
0 0 15x -
After combustion total volume
330 = 300 + 15x
x = 2
Volume of O2 used
y = 12
So hydrocarbon is = C2H12
None of the options matches it therefore it is a BONUS.
----------------------------------------------------------------------
Alternatively Solution
15ml
0 0 15x -
Volume of O2 used
If further information (i.e., 330 ml) is neglected, option (C3H8 ) only satisfy the above equation.
View Full Answer(1)Which of the following is an anionic detergent?
Option: 1 Sodium stearate
Option: 2 Sodium lauryl sulphate
Option: 3 Cetyltrimethyl ammonium bromide
Option: 4 Glyceryl oleate
As we have learned
Phenol formation from Benzenesulphonic acid -
Acidification of sodium salt gives phenol.
- wherein
Sodium lauryl sulphate has anionic charge
View Full Answer(1)
The absolute configuration of is :
Option: 1 (2R, 3S)
Option: 2 (2S, 3R)
Option: 3 (2S, 3S)
Option: 4 (2R, 3R)
As we learnt ,
Chiral Carbon -
Those carbon on which four different groups are present.
- wherein
For C2
This rotation suggests R but the least prior group is at horizontal position so the configuration is R.
For C3
This rotation suggests S but the least prior group is at horizontal position so the configuration is S.
The equilibrium constant at 298 K for a reaction A+BC+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L−1) will be :
Option: 1 0.182
Option: 2 0.818
Option: 3 0.818
Option: 4 1.182
As we dicussed in the concept
Law of Chemical equilibrium -
At a given temperature, the product of concentration of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentration of the reactants raised to their individual stoichiometric coefficients has a constant value.
- wherein
are equilibrium concentration
For reaction
Initial concentration IM IM IM IM
At equilibarium if degree of dissociation is then
1- 1-
H
1+
9=
Concentration of D is 1+=I+
=1.818
View Full Answer(1)The heats of combustion of carbon and carbon monoxide are −393.5 and −283.5 kJ mol−1, respectively. The heat of formation (in kJ) of carbon monoxide per mole is:
Option: 1 110.5
Option: 2 676.5
Option: 3 -676.5
Option: 4 -110
Therefore, Option(4) is correct
View Full Answer(1)The concentration of fluoride, lead, nitrate, and iron in a water sample from an underground lake was found to be 1 ppm, 40 ppm, 100 ppm and 0.2 ppm, respectively. This water is unsuitable for drinking due to high concentration of :
Option: 1 Fluoride
Option: 10 Lead
Option: 19 Nitrate
Option: 36 Iron
As we learned in concept
Hard Water -
It contains calcium and Magnesium salt in the form of hydrogen carbonate , chloride and sulphate
- wherein
Hard water does not give Lathers with soap.
Maximum permissible concentration of constituents
lead : 50 ppm
nitrate : 50 ppm
Iron : 0.2 ppm
fluoride: 1 ppm
Therefore, option (3) is correct.
View Full Answer(1)Which one of the following statements about water is FALSE?
Option: 1 Water is oxidized to oxygen during photosynthesis..
Option: 2 Water can act both as an acid and as a base
Option: 3 There is extensive intramolecular hydrogen bonding in the condensed phase
Option: 4 Ice formed by heavy water sinks in normal water.
There is intermolecular hydrogen bounding in condensed phase of water and not intramolecular hydrogen bonding.
During Photosynthesis, Water is oxidised to Oxygen according to the reaction
Water can react with both acid as well as base
View Full Answer(1)The correct sequence of reagents for the following conversion will be :
Option: 1
Option: 3
Option: 5
,
Option: 7
,
?
Among the following compounds, the increasing order of their basic strength is
Option: 1 (I) < (II) < (IV) < (III)
Option: 2 (I) < (II) < (III) < (IV)
Option: 3 (II) < (I) < (IV) < (III)
Option: 4 (II) < (I) < (III) < (IV)
Among the following compounds, the increasing order of their basic strength is (II)<(I)<(IV)<(III)
(III) is most basic due to +I effect of −CH3 group attached to N. This increases electron density on N so that N can easily donate its lone pair of electrons to suitable acid.
(II) is least basic as the lone pair of electrons on N is part of pi electrons of aromatic ring. Donation of this lone pair of electrons will break the stability of the aromatic ring.
(I) is less basic than (IV) as the lone pair of electrons on N is in conjugation with aromatic ring.
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