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The set of points where the function \mathrm{f(x)=|x-1| e^x}   is differentiable is

Option: 1

R


Option: 2

\mathrm{R-|1|}


Option: 3

\mathrm{R-|-1|}


Option: 4

\mathrm{R-|0|}


Answers (1)

best_answer

Since |x-1| is not differentiable at x=1. So.  \mathrm{f(x)=|x-1| c^{\prime}}  is not differentiable at x=1. Hence, the requried set is R-|1|.

Posted by

Ritika Kankaria

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