Filter By

## All Questions

#### Boolean relation at the output stage - Y for the following circuit is :   Option: 1 Option: 2  Option: 3    Option: 4

The first part of the given circuit represents or gate whose output is A+B

The second part of the circuit is NOT gate whose input is A+B and output is

So the correct option is 4.

## Crack CUET with india's "Best Teachers"

• HD Video Lectures
• Unlimited Mock Tests
• Faculty Support

#### Which of the following gives a reversible operation?   Option: 1 Option: 2 Option: 3  Option: 4

For reversible operation, NOT gate is used. If an input is$A$then output=$\bar{A}$. The following circuit represents the NOT gate

So Option (2) is correct.

#### The current i in the  network is : Option: 1 Option: 2 Option: 3 Option: 4

Both diodes are in reverse biased

So new circuits can be drawn as

So

Hence the correct option is (1).

## JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

#### In the given circuit, the value of Y is : Option: 1 toggles between 0 and 1 Option: 2 1 Option: 3 0 Option: 4 will not execute

In NAND gate, when

$\\y=\overline{A.\overline{A.B}}\\Given\\A=1,\ B=0\\\Rightarrow A.B=0\\ \overline{A.B}=1\ and \ A.\overline{A.B}=1\ \\ \ therefore\ \overline{A.\overline{A.B}}=0$

Hence the correct option is (3)

#### Both the diodes used in the circuit shown are assumed to be ideal and have negligible resistance when these are forward biased. Built-in potential in each diode is 0.7V. For the input voltages shown in the figure, the voltage (in Volts) at a point A is ______________     Option: 1 12 Option: 2 10 Option: 3 40 Option: 4 24

We want to find V

By applying kvl in AEFBA

12.7 - 0.7 - V= 0.

implies

V = 12V

Hence the correct option is (1).

## NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

#### A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of in the collector circuit is 0.6 V. If the current gain factor is 24, then the base current is _______ . (Round off to the Nearest Integer)

\begin{aligned} &V_{C C}=10 \mathrm{~V} \\ &I_{C} R_{C}=0.6 \mathrm{~V} \\ &I_{C}(1000)=0.6 \end{aligned}

$I_{c}=6 \times 10^{-4} \mathrm{~A}$

\begin{aligned} B=\frac{I_{C}}{I_{B}} &=24 \\ I_{B} &=\frac{6}{24} \times 10^{-4} . \\ &=0.25 \times 10^{-4} \\ I_{B} &=25 \mu \mathrm{A} \end{aligned}

#### Find the truth table for the function represented in the following figure.Option: 1Option: 2Option: 3Option: 4

$Y=A \cdot B+\bar{B}$

$\begin{array}{|c|c|c|} \hline A & B & Y=A \cdot B+\bar{B} \\ \hline 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \hline \end{array}$

The correct option is (2)

## Crack CUET with india's "Best Teachers"

• HD Video Lectures
• Unlimited Mock Tests
• Faculty Support

#### Statement I: By doping silicon semiconductor with pentavalent material,the electrons density increases. Statement II : The n-type semiconductor has net negative charge. In the light of the above statements,choose the most appropriate answer from the options given below: Option: 1 Both statement I and Statement II are false. Option: 2  statement I  is true but Statement II is false. Option: 3 Statement I is false but Statement II is true. Option: 4 Both Statement I and Statement II are true.

Statement I
By doping silicon semiconductors with pentavalent material.
$n_{e}> > n_{h}$
Statement II
The n-type semiconductor has a net negative charge
Both the statements are true
Hence, the correct option is (4)

#### Identify the logic operation carried out by the given circuit :Option: 1 OROption: 2 ANDOption: 3 NANDOption: 4 NOR

$Z= \bar{A}.\bar{B} \\ or \\ Z= \overline{A+B}$
$\therefore$ The logic operation carried out in the above circuit is equivalent to NOR Gate
The correct option is (4)