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A transistor is connected in common emitter circuit configuration, the collector supply voltage is 10 V and the voltage drop across a resistor of 1000 \Omega in the collector circuit is 0.6 V. If the current gain factor (\beta ) is 24, then the base current is _______ \mu A. (Round off to the Nearest Integer)
 

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\begin{aligned} &V_{C C}=10 \mathrm{~V} \\ &I_{C} R_{C}=0.6 \mathrm{~V} \\ &I_{C}(1000)=0.6 \end{aligned}

I_{c}=6 \times 10^{-4} \mathrm{~A}

\begin{aligned} B=\frac{I_{C}}{I_{B}} &=24 \\ I_{B} &=\frac{6}{24} \times 10^{-4} . \\ &=0.25 \times 10^{-4} \\ I_{B} &=25 \mu \mathrm{A} \end{aligned}

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vishal kumar

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