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Q.2.    Find the area of any one door in your house.

suppose the length of door is 2m and breadth is 0.5 m 

then the area of door = length\times breadth=2\times0.5=1m^2

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Posted by

Safeer PP

   Find the area of the floor of your classroom.

If floor length is 3m and breadth is 2m then 

 floor \ area=length\times breadth=3\times2=6m^2

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Posted by

Safeer PP

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Find various objects from your surroundings which have regular shapes and find their perimeters.

I found the various objects from my surroundings those are plastics water bottle , chair , soap box, pen holder. And their perimeter are 25 cm square,45 cm square,15cm square,16cm square

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Posted by

Satyajeet Kumar

Find the perimeter of the following rectangles:

Length of rectangle Breadth of rectangle Perimeter by adding all sides perimeter by 2\times(length + breadth)
25 cm  12 cm =25+12+25+12=74 cm \\2\times(25+12)\\2\times37=74\ cm
0.5 cm 0.25cm =0.5+0.25+0.5+0.25=1.5cm \\2\times(0.25+0.5)\\2\times0.75=1.5\ cm
18 cm 15 cm =18+15+18+15=66 cm \\2\times(18+15)\\2\times33=66\ cm
10.5 cm 8.5 cm =10.5+8.5+10.5+8.5=38 cm \\2\times(10.5+8.5)\\2\times19=38\ cm

 

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Posted by

Safeer PP

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  Find the perimeter of the following figures:

         

         Perimeter = AB + BC + CD + DA
         = __+__+__+__
         = ______

      

        Perimeter = AB + BC + CD + DA
        = __ + __ + __+ __
        = ______

      

          Perimeter = AB + BC + CD + DE + EF + FG + GH +HI + IJ + JK + KL + LA
          = __ + __ +__ + __ + __ +  __ + __ + __ +__+ __ + __ + __
          = ______

         

           Perimeter = AB + BC + CD + DE + EF+ FA
           = __ + __ + __ + __ + __ + __
           = ______

  Find the perimeter of the following figures:

         

         Perimeter = AB + BC + CD + DA
         = 40+10+40+10
         = 100

      

        Perimeter = AB + BC + CD + DA
      =5+5+5+5=20

      

          Perimeter = AB + BC + CD + DE + EF + FG + GH +HI + IJ + JK + KL + LA
                           =1+3+3+1+3+3+1+3+3+1+3+3=28 cm 

         

           Perimeter = AB + BC + CD + DE + EF+ FA
                           =100 + 120 + 90 + 45+ 60 +80=495 cm

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Posted by

Safeer PP

  Meera went to a park 150 m long and 80 m wide. She took one complete round on its boundary. What is the distance covered by her?

Length of park = 150m

Breadth of park = 80m

Perimeter of rectangular park = 2( l+b )

                                                       = 2( 150 + 80 )

                                                     = 2× 230

                                                      =  460

Ans = 460 m 

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Posted by

Ridhima vats

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Measure and write the length of the four sides of the top of your study table.

AB = ____ cm
BC = ____ cm
CD = ____ cm
DA = ____ cm

Now, the sum of the lengths of the four sides
= AB + BC + CD + DA
= ___ cm +___ cm +___ cm +___ cm
= _____ cm

What is the perimeter?

AB = 100 cm

BC = 60 cm

CD = 100 cm

DA = 60 cm

AB + BC + CD + DA + AB = 320

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Posted by

Vaghamshi kirtan

Q 12.     How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:

             (a) 100 cm and 144 cm
             (b) 70 cm and 36 cm.

Given that,
the length and breadth of the tiles are 12 cm and 5 cm

Therefore, the area of the tiles 
= length \times breadth
= 12 cm \times 5 cm
= 60 cm2

Now, (a) For 100 cm and 144 cm rectangular region,
Area of region =  length \times breadth
                        = 14,400 cm2

Therefore, the number of tiles needed = \frac{14,400}{60}=240 tiles

(b)  For 70 cm and 36 cm rectangular region,
Area of region =  length \times breadth
                        = 70 cm \times 36 cm
                        = 2520 m2

Required number of tiles = \frac{2520}{60}=42

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Posted by

manish

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Q 11.     Split the following shapes into rectangles and find their areas. (The measures are given in centimetres)

                

(a) Split the given figure into a small rectangle, as shown here;

Now, the area of the rectangle (I) = l\times b = 12 \times 2 = 24cm^2 
the area of the rectangle (II) = l\times b = 8 \times 2=  16cm^2

Therefore, Total area = 24cm^2 + 16cm^2 = 40cm^2

(b) Split the given figure into a small rectangle, as shown here;

Now, the area of the rectangle (I) = l\times b = 7 \times7 = 49 cm^2
the area of the rectangle (II) = l\times b = 21 \times 7= 147 cm^2
Now, the area of the rectangle (III) = l\times b = 7 \times7 = 49 cm^2

Therefore, Total area = 49cm^2 + 147cm^2 + 49cm^2 = 245 cm^2

(c) Split the given figure into a small rectangle, as shown here; 

Now, the area of the rectangle (I) = l\times b = 2 \times 1 =2 cm^2
the area of the rectangle (II) = l\times b = 5 \times 1= 5 cm^2
Now, the area of the rectangle (III) = l\times b = 2 \times1 = 2 cm^2

Therefore, Total area = 2 cm^2 + 5cm^2 + 2cm^2 = 9cm^2

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Posted by

manish

Q 10.     By splitting the following figures into rectangles, find their areas (The measures are given in centimetres).

                

(a) Split the given figures into small rectangular parts as shown here;

Now, the area of the rectangle (I) = l\times b = 4 \times 3 = 12 cm^2
the area of the rectangle (II) = l\times b = 3 \times 2= 6 cm^2
the area of the rectangle (III) = l\times b = 4 \times 1 = 4 cm^2
the area of the rectangle (IV) = l\times b = 3 \times 2 = 6 cm^2

So, the total area of the figure = sum area of all rectangles
                                                 = (12 + 6 + 4 + 6) cm^2
                                                 = 28 cm^2

(b) Split the given figure into smalle rectangles  as shown here;

the area of the rectangle (I) = l\times b = 3 \times 1 = 3 cm^2
the area of the rectangle (II) = l\times b = 3 \times 1= 3 cm^2
the area of the rectangle (III) = l\times b = 3 \times 1 = 3 cm^2?

Therefore, the total area of the figure = sum of the area of all the small rectangles
                                                             = 3+3+3
                                                             = 9cm^2

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Posted by

manish

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