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 The rate of a reaction quadruples when the temperature changes from 300 to 310 K. The activation energy of this reaction is : (Assume activation energy and preexponential factor are independent of temperature; ln 2=0.693; R=8.314 J mol−1 K−1)
Option: 1  107.2 kJ mol−1
Option: 2 53.6 kJ mol−1
Option: 3 26.8 kJ mol−1
Option: 4 214.4 kJ mol−1  
 

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\\\text{The rate of the reaction can be written as:}\\ \\ ln\frac{K_{2}}{K_{1}}= \frac{E_{a}}{R}[\frac{1}{T_{1}}-\frac{1}{T_{2}}]\\ \\ ln\frac{4}{1}= \frac{E_{a}}{8.314}[\frac{1}{300}-\frac{1}{310}]\\ \\ E_{a}= 107.2 \ kJ/mol

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