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  • 0.3 g of acid is neutralised by 40 cm3 .125N NaOH .equvivalent mass of acid is

0.3 g of acid is neutralized by 40 cm3 of 0.125N NaOH .equvivalent mass of acid is

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\\40 \mathrm{cm}^{3}$ of $0.125 \mathrm{N}$ NaOH neutralize acid $=0.3 \mathrm{g}$ \\ $1000 \mathrm{cm}^{3}$ of $1 \mathrm{N} \mathrm{NaOH}$ will neutralize acid\\ $=\frac{0.3}{40} \times \frac{1000}{0.125} g=60 g$ \\ $1000 \mathrm{cm}^{3}$ of $1 \mathrm{N} \ \mathrm{NaOH}$ contains one gram equivalent of the acid. Hence equivalent weight of acid=60

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