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  • 12 stones, numbered from 0 to 9, are in a small container. How many different combinations of three digits could be made by taking them out of the container without any replacements?

12 stones, numbered from 0 to 9, are in a small container. How many different combinations of three digits could be made by taking them out of the container without any replacements?

 

Option: 1

1140


Option: 2

1320 


Option: 3

1420 

 


Option: 4

1510


Answers (1)

best_answer

The number of permutations of 3 digits chosen from 12 stones is given by,

^{12}P_3
Using the Permutations formula,

{ }^n P_r=\frac{n !}{(n-r) !}
Solving the above term to get,

^{12}P_3=\frac{12!}{(12-3)!}

^{12}P_3=\frac{12!}{(9)!}

^{12}P_3= 1320
Therefore, in 1320 ways, 3 digits can be formed from 12 stones.

Posted by

seema garhwal

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