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250 g of water and equal volume of alcohol of mass 20 gm are replaced succesively in the same caloriemeter and cool from 60 C to 55 C in 130 second and 67 second respectively . If the water equivalemnt of the caloriemeter is 10 gm then the specific heat of alcohol is 

Option: 1

1.30


Option: 2

0.67 


Option: 3

0.62 


Option: 4

0.98 


Answers (1)

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As we have learned

Water Equivalent -

The mass of water which would obserb or evolve the same amount of heat as is done by the body in rising or falling though the same range temperature.

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 Heat lost by water and caloriemeter = (250+10 )*5 = 1300 cal 

Rate of heat loss = 1300/130 = 10 cal /s 

Heat lost by alcohol and caloriemeter = (200s + 10 ) * 5 = 1000 s + 50 

Rate of heat lost = (1000 s + 50) / 67 

Rate of heat loss is equal in both cases then 

s = 0.62 

Posted by

vishal kumar

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