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  • 250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is _______ (Nearest integer) <img alt="\left(\m

250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is _______ \times 10^{21} (Nearest integer) \left(\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23}\right)
 

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\\\text{Millimoles of }\mathrm{HCl}=500 \times 1=500\\ \\\text{Millinoles of }\mathrm{NaOH}=250 \times 0.5=125\\ \\\therefore \text{Millimoles of unreacted} \; \mathrm{HCl}=375.

\\\therefore \text{Moles of }\mathrm{HCl}=0.375\\ \\\therefore \text{Molecules of } \mathrm{HCl}=0.375 \times 6.022 \times 10^{23}

                                            \begin{aligned} &=2.26 \times 10^{23} \\ \\&=226 \times 10^{21} \end{aligned}

Hence, the correct answer is 226.

Posted by

sudhir.kumar

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