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  • 64 identical drops each charged upto potential of 10 mV are combined to form a bigger drop. The potential of the bigger drop will be _____ mV.Option: 1

64 identical drops each charged upto potential of 10 mV are combined to form a bigger drop. The potential of the bigger drop will be _____ mV.

Option: 1

160


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

We know \mathrm{V}=\frac{\mathrm{kq}}{\mathrm{r}}, \quad \mathrm{q}^{\prime}=64 \mathrm{q}
Voulme remain const so
$$ \begin{aligned} & \frac{4}{3} \pi \mathrm{r}^3 \times 64=\frac{4}{3} \pi \mathrm{R}^3 \\ & \mathrm{R}=4 \mathrm{r} \end{aligned}
Now new potential \mathrm{V}^{\prime}=\frac{\mathrm{K} 64 \mathrm{q}}{4 \mathrm{r}}=\frac{16 \mathrm{kq}}{\mathrm{r}}
$$ \begin{aligned} & \mathrm{V}^{\prime}=16 . \mathrm{V} \text { and } \mathrm{V}=\frac{\mathrm{Kq}}{\mathrm{r}}=10 \mathrm{mV} \\ & \mathrm{V}^{\prime}=16 \times 10 \times 10^{-3} \\ & \mathrm{~V}^{\prime}=0.16 \mathrm{~V} \end{aligned}
OR V' =160 \mathrm{mV}

Posted by

avinash.dongre

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