Get Answers to all your Questions

header-bg qa

A 1 m long metal rod XY completes the circuit as shown in figure. The plane of the circuit is perpendicular to the magnetic field of flux density 0.15 T. If the resistance of the circuit is 5\Omega,the force needed to move the rod in direction, as indicated, with a constant speed of 4 m/s will be _______ 10^{-3} \mathrm{~N}
                                                  

Option: 1

18


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{F}=\mathrm{I} \ell \mathrm{B}=\left(\frac{\mathrm{e}}{\mathrm{R}}\right) \ell \mathrm{B}=\frac{(\mathrm{B} \ell) \mathrm{B} \ell}{\mathrm{R}}=\frac{\mathrm{B}^2 \ell^2 v}{\mathrm{R}} \\ & =\frac{(\cdot 15)^2 \times(1)^2 \times 4}{5}=180 \times 10^{-4} \\ & =18 \times 10^{-3}=18 \text { Ans. } \end{aligned}

Posted by

mansi

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE