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  • A 10 V battery with internal resistance1\Omega and a 15V battery with internal resistance 0.6\Omega are connected in parallel to a voltmeter

A 10 V battery with internal resistance1\Omega and a 15V battery with internal resistance 0.6\Omega are connected in parallel to a voltmeter (see figure). The reading in the voltmeter will be close to :

Answers (1)

The potential according to given circuit diagram is as followsThe net resistance is given by

\begin{array}{c} \frac{1}{R}=1+\frac{10}{6}=\frac{16}{6} \\ \text {or } \quad R=\frac{3}{8} \text { ohm } \end{array} 

\begin{aligned} &\text {The net potential } V=15-10=5 \text {Volt}\\ &\text {Therefore the current } I=\frac{V}{R}=\frac{5 \times 8}{3}=13.3 \mathrm{A}\\ &\text { There fore potential across voltmeter }=13.3 \times 1=13.3 \mathrm{Volt} \end{aligned} 

 

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Satyajeet Kumar

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