A 4 g bullet is fired horizontally with a speed of 300 m/s into 0.8 kg block of wood at rest on a table. If the coefficient of friction between

 the block and the table is  0.3, how far will the block slide approximately ?

Answers (1)

As we have learned

Coefficient of Friction(µ) -

Ratio of static friction to the normal \mu_{s}=\frac{F}{R}

F = Static friction.

- wherein

*    Unit less

*    Dimensionsless

 

 

After coliision , common velocity 

v = \frac{0.004 \times 300}{0.804}= \frac{300 \times 4}{804 } = 1.5 m/s

\mu = 0.3

Decelleartion a = \mu g = 0.3 \times 9.8 = 2.94 m /s^2

Distance travelled S = \frac{u^2 }{2a } = \frac{(1.5)^2}{2\times 2.9 }= 0.98 m

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