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  • A ball is released from the surface of the earth along a tunnel such that the tunnel is along the diameter of the earth , then the motion of this ball will have time period equals to T<su

A ball is released from the surface of the earth along a tunnel such that the tunnel is along the diameter of the earth , then the motion of this ball will have time period equals to T1 and if another ball of twice the mass of the ball in the first case is released along any of the chord of the earth and its motion is having a time period of T2. Then which of the given relation will be true?  

Option: 1

T_2 = \sqrt{2}.T_1   because the mass of second case is two times of the first case


Option: 2

T_2 = T_1


Option: 3

Can not say as the distance of the chord is not given from the center of the earth.


Option: 4

\sqrt{2}. T_1 =T_2


Answers (1)

best_answer

 

 

The time period of oscillation is the same in both cases whether the tunnel is along the diameter or along the chord. It does not depends on the mass. So, T_2 = T_1

Posted by

Ajit Kumar Dubey

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