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A bar magnet with a magnetic moment \mathrm{5.0Am^{2}} is placed in parallel position relative to a magnetic field of \mathrm{0.4 T}. The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is _______.

Option: 1

\mathrm{1J}


Option: 2

\mathrm{4J}


Option: 3

\mathrm{2J}


Option: 4

\mathrm{zero}


Answers (1)

best_answer

\begin{aligned} & W=M B\left(\cos \theta_1-\cos \theta_2\right) \\ & W=M B\left(\cos 0^{\circ}-\cos 180^{\circ}\right) \\ & W=2 M B \\ & W=2 \times 5 \times 0.4 \\ & W=4 \mathrm{~J} \end{aligned}

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Shailly goel

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