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A bat emits ultrasonic sound of frequency, 200 \mathrm{KHZ} in air. If this sound meets a water surface, the wavelengths of the reflected and transmitted sound are (speed of sound in air) =332 \mathrm{~m} / \mathrm{s} and in water =1600 \mathrm{~m} / \mathrm{s}.

Option: 1

1.66mm and 8mm


Option: 2

1.22 mm and 6mm


Option: 3

1.32mm and 7mm


Option: 4

1.42mm and 3mm


Answers (1)

best_answer

Here, n=200 \mathrm{kHz}=200 \times 10^3 \mathrm{~Hz}

 n=2 \times 10^5 \mathrm{HZ} \\

V_a=332 \mathrm{~m} / \mathrm{s}      V_w=1600 \mathrm{~m} / \mathrm{s}

Frequency of both the reflected and transmitted sound remains unchanged wavelength of reflected sound

\lambda_a=\frac{v_a}{n}=\frac{332}{2 \times 105}=166 \times 10^{-5} \mathrm{~m}=1.66 \times 10^{-3} \mathrm{~m} \\\lambda_a=1.66 \mathrm{~mm}

Wavelength of transmitted sound

\lambda w=\frac{v_w}{n}=\frac{1600}{2 \times 10^5}=800 \times 10^{-5} \mathrm{~m} \\

=8.0 \times 10^{-3} \mathrm{~m} \\

\lambda_w=8 \mathrm{~mm}

Posted by

Suraj Bhandari

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