A battery of 3.0 V is connected to a resistor dissipating of 0.5W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is:
Option: 1 0.50W
Option: 2 0.072 W
Option: 3 0.10 W
Option: 4 0.125 W
Also,
Power dissipated across 'r'
Now
iR =2.5 .....(1)
ir =0.5 .......(2)
From equation (1) and (2)
we get
Now,
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