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A battery of \mathrm{6 V} is connected to the circuit as shown below. The current I drawn from the battery is:

Option: 1

\mathrm{1 A}


Option: 2

\mathrm{2 A}


Option: 3

\mathrm{\frac{6}{11} A}


Option: 4

\mathrm{\frac{4}{3} A}


Answers (1)

best_answer

Here,there won't be current through 5\Omega resistance as it is balanced wheatstone network

\mathrm{I=\frac{6}{6}=1A}

Hence (1) is correct option.

Posted by

Ritika Kankaria

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