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A beam of light travelling along $\mathrm{ X-axis}$ is described by the electric field $\mathrm{ E_{y}=900 \sin \omega(\mathrm{t}-x / c).}$ The ratio of electric force to magnetic force on a charge $\mathrm{ \mathrm{q}}$ moving along $\mathrm{ Y-axis}$ with a speed of $\mathrm{ 3 \times 10^{7} \mathrm{~ms}^{-1}}$ will be : $\mathrm{ \text { (Given speed of light }=3 \times 10^{8} \mathrm{~ms}^{-1}}$
Option: 1
$1:1$

Option: 2
$1: 10$

Option: 3
$10:1$

Option: 4
$1:2$

Answers (1)

best_answer

$\mathrm{E_y=900 \sin (\omega(t-x / c)) }$

$\mathrm{\frac{F_E}{F_M}=\frac{q E}{q \text { VBsin } 90^{\circ}} }$

$\mathrm{V=3 \times 10^7 \mathrm{~m} / \mathrm{s} }$

$\mathrm{\frac{E}{B}=3 \times 10^8 \mathrm{~m} / \mathrm{s} }$

$\mathrm{\frac{F_E}{F_M}=\frac{E}{V B}=\frac{3 \times 10^8}{3 \times 10^7}=\frac{10}{1}}$

Hence 3 is correct option.

Posted by

rishi.raj

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