A block kept on a rough inclined plane , as shown in the figure , remains at rest upto a maximum force 2 N down the inclined plane. The maximum external external force up the inclined plane that does not move the block is 10 N . The coefficient of static friction between the block and the plane is :

[Take g = 10 m/s2

Minimum Force to move a body downward along the surface of Inclined Plane -

Use condition of equilibrium.

$R+P sin \alpha=W cos \lambda$

$F= P cos \alpha + W sin \lambda$

Use  $F=\mu R$

$P=\frac{W sin(\theta-\lambda)}{cos(\alpha-\theta)}$

- wherein

P = Pulling force

$\alpha=$ Angle of P with horizontal

$\lambda=$ Inclined angle

R = Reaction

W = Weight

For 2N force

$2+mg \sin \theta = \mu mg\cos 30$ ........(1)

For 10N force

$10= mg\sin 30+\mu mg\cos 30$ ........(2)

From (1) and (2)

$12 = 2\mu mg \cos \left ( 30 \right )$

$8=mg\sin 30$

$\Rightarrow \frac{12}{8} = \mu \cot 30 = 2\mu \times \sqrt{3}$

$\mu =\frac{\sqrt{3}}{2}$

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 6999/- ₹ 5/-
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-