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  • A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to surface of the table, the block slides through a distance

A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in
the direction parallel to surface of the table, the block slides through a distance of 50 m in an interval
of time 10 s. Coefficient of kinetic friction is (given ,g = 10 ms^{-2} ) 

Option: 1

0.60


Option: 2

  0.25 


Option: 3

0.75


Option: 4

0.50


Answers (1)

S=ut+\frac{1}{2}\, \, at^{2}         

                                                    

\begin{aligned} & 50=0 \times \mathrm{t}+\frac{1}{2} \times \mathrm{a} \times(10)^2 \\ & 50=\frac{1}{2} \times \mathrm{a} \times 100 \\ & \mathrm{a}=\frac{100}{100} \Rightarrow \mathrm{a}=1 \mathrm{~m} / \mathrm{s}^2 \\ & \sum \mathrm{F}_{\mathrm{x}}=\mathrm{ma} \mathrm{x} \\ & 30-\mu \mathrm{mg}=\mathrm{ma} \\ & 30-\mu \times 50=5 \\ & 50 \mu=25 \end{aligned}

\begin{aligned} & \mu=\frac{25}{50} \\ & =\frac{1}{2} \\ & \Rightarrow \mu=0.5 \end{aligned}  

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Kshitij

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