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A body of mass 1 kg rests on a horizontal floor with which it has a coefficient of static friction \frac{1}{\sqrt{3}}. It is desired to make the body move by applying the minimum possible force F.N. The value of F will be ____________.(Round off to the Nearest Integer). [Take g = 10 ms -2 ]
Option: 1 5
Option: 2 10
Option: 3 15
Option: 4 20

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\begin{array}{l} F \cos \theta=\mu N \\ \\ F \sin \theta+N=m g \\ \\ \Rightarrow F=\frac{\mu m g}{\cos \theta+\mu \sin \theta} \\ \\ F_{\min }=\frac{\mu m g}{\sqrt{1+\mu^{2}}}=\frac{\frac{1}{\sqrt{3}} \times 10}{\frac{2}{\sqrt{3}}}=5 \end{array}

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Deependra Verma

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