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  • A body start rotating about its centre with angular acceleration  <img alt="=\alpha =0.2\; rad/s^{2}" src="https://learn.careers360.com/latex-image/?%3D%5Calpha%20%3D0.2%5C%3B%20rad/s%5E%

A body start rotating about its centre with angular acceleration  =\alpha =0.2\; rad/s^{2}

Then what is its angular displacement (in rad) in 4^{th} second

 

Option: 1 0.4

Option: 2 0.5

Option: 3 0.6

Option: 4 0.7

Answers (1)

best_answer

 

 

 

 

\theta _{n}=\omega _{i}+\frac{\alpha }{2}\left ( 2n-1 \right )

As

Here

\omega _{i}=0

\alpha =0.2\; rad/s^{2}

n=4

So, \theta _{n}=0+\frac{0.2}{2}(2\ast 4-1)=0.7\; rad

Posted by

Rakesh

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