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A bullet is shot vertically downwards with an initial velocity of \mathrm{ 100 \mathrm{~m} / \mathrm{s}} from a certain height. Within \mathrm{ 10 \mathrm{~s},} the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time \mathrm{t=20 s} will be: \mathrm{\left(\text { Take } \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)}.

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

\mathrm{u \rightarrow} Initial velocity of bullet

\mathrm{v \rightarrow} Velocity of bullet when it reaches the ground

\mathrm{V =u+a t }

\mathrm{V =(-100)+(-10) \times 10 }

\mathrm{V =-200 \mathrm{~m} / \mathrm{s} }

Ball comes to rest at \mathrm{t=10\: s } immediately affer the collision.

The first option is the correct depiction of the situation.

Hence 1 is correct option

Posted by

Sumit Saini

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