Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

A bullet of $10 \mathrm{~g}$ , moving with velocity $v$ , collides head-on with the stationary bob of a pendulum and recoils with velocity $100 \mathrm{~m} / \mathrm{s}.$ The length of the pendulum is $0.5 \mathrm{~m}$ and mass of the bob is $1 \mathrm{~kg}.$ The minimum value of $v=$ _________ $\mathrm{m} / \mathrm{s}$ so that the pendulum describes a circle.
(Assume the string to be inextensible and $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}$ )

Answers (1)

best_answer

By linear momentum conservation

$m_{1}u_{1}+m_{2}u_{2}= m_{1}V_{1}+m_{2}V_{2}\\$

$10\times 10^{-3}\left ( V\right )+1(0)= 10^{-2}\times (-100)+(1)V_{2}\\$

$V_{2}= 1+10^{-2}V$

For the Bob to just complete the vertical circular motion

$V_{2}= \sqrt{5gR}$

here $R= l= 0.5\\$

$1+10^{-2}V= \sqrt{25}\\$

$1+10^{-2}= V5\\$

$\Rightarrow V= 400(m/s)$

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

Amrita BTech Admission 2025: JEE Main-based registration deadline extended to August 30

Latest Question